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Wireshark data packet Time internal

0

I capture two wireshark packet, the time stamp is as below:

2.188099000 2.243311000

Can someone inform me how much is the time internal for those two packets?

asked 02 Jun '14, 19:31

rabbit's gravatar image

rabbit
1445
accept rate: 0%

Are you asking someone to subtract the first time from the second time for you?

(02 Jun '14, 21:27) Rooster_50

One Answer:

1

O.K. I'll do it ;-))

abs(2.188099000 - 2.243311000) = 0.055212

So, the answer is: 0.055212

answered 03 Jun '14, 00:11

Kurt%20Knochner's gravatar image

Kurt Knochner ♦
24.8k1039237
accept rate: 15%

I made the comment an answer, as I believe it is a valid answer ;-))

(03 Jun '14, 14:34) Kurt Knochner ♦