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Understanding packet length

I'm using Wireshark to learn about my network and better understand MTU and packet sizes, and I'm looking for some clarity on this example. Here I ran ping 192.168.10.53 -s 9000 -M do from a CentOS machine and I am capturing on the receiving machine which is Windows. So I expect the ICMP packet should contain 9000 bytes of data plus 8 byte header.

Wireshark shows the frame is 9042 bytes on wire (14 Ethernet header + 20 IPv4 header + 9008 ICMP)
The ICMP packet shows 8992 bytes of data plus 8 byte header.
What happened to the extra 8 bytes of data?

Understanding packet length

I'm using Wireshark to learn about my network and better understand MTU and packet sizes, and I'm looking for some clarity on this example. Here I ran ping 192.168.10.53 -s 9000 -M do from a CentOS machine and I am capturing on the receiving machine which is Windows. So I expect the ICMP packet should contain 9000 bytes of data plus 8 byte header.

Wireshark shows the frame is 9042 bytes on wire (14 Ethernet header + 20 IPv4 header + 9008 ICMP)
The ICMP packet shows 8992 bytes of data plus 8 byte header.
What happened to the extra 8 bytes of data?

Here's the pcap: https://mega.nz/#!w0ohBYbA!lXEHtnrGqfF3T2j79hnOA2fQK6yomzCx2MMzs77ZAh0