Ask Your Question
2

Can you explain this TCP sequence

asked 2018-07-18 08:13:13 +0000

Luca gravatar image

updated 2018-07-18 08:52:40 +0000

grahamb gravatar image

Hello, Could anyone explain the behavior I observe below?

I have the following registration extract: a packet with seq=3020828 is sent out but never acknowledged. The packet is also retransmitted multiple times, but the receiver keeps acknowledging the previous seq:

 57788 2018-07-16 15:36:20.552618000 10.245.40.74 10.245.54.13 TCP 2974 64613 -> 14004 [ACK] Seq=3020828 Ack=73535403 Win=65536 Len=2920

...

58376 2018-07-16 15:36:20.851770000 10.245.40.74 10.245.54.13 TCP 1514 [TCP Retransmission] 
64613 -> 14004 [ACK] Seq=3020828 Ack=74313583 Win=1296 Len=1460

58378 2018-07-16 15:36:21.101721000 10.245.54.13 10.245.40.74 TCP 1350 14004 -> 64613 [PSH, ACK] Seq=74313583 Ack=3020828 Win=4096 Len=1296 [TCP segment of a reassembled PDU]

...

60992 2018-07-16 15:36:22.652682000 10.245.40.74 10.245.54.13 TCP 1514 [TCP Retransmission] 64613 -> 14004 [ACK] Seq=3020828 Ack=77762103 Win=1296 Len=1460

60994 2018-07-16 15:36:22.658427000 10.245.54.13 10.245.40.74 TCP 1514 14004 -> 64613 [ACK] Seq=77762103 Ack=3020828 Win=4096 Len=1460 [TCP segment of a reassembled PDU]

On the receiver side, I do see the packet coming in, but it is someone ignored and it keeps acknowledging the previous seq:

13878 2018-07-16 15:36:20.825430000 10.245.40.74 10.245.54.13 TCP 1514 [TCP Retransmission] 64613 -> 14004 [ACK] Seq=3020828 Ack=74313583 Win=1296 Len=1460

18810 2018-07-16 15:36:36.047313000 10.245.54.13 10.245.40.74 TCP 29254 14004 -> 64613 [ACK] Seq=114189103 Ack=3020828 Win=20480 Len=29200 [TCP segment of a reassembled PDU]

...

13991 2018-07-16 15:36:21.425465000 10.245.40.74 10.245.54.13 TCP 1514 [TCP Retransmission] 64613 -> 14004 [ACK] Seq=3020828 Ack=74834803 Win=1296 Len=1460

13993 2018-07-16 15:36:21.433178000 10.245.54.13 10.245.40.74 TCP 27794 14004 -> 64613 [ACK] Seq=74834803 Ack=3020828 Win=4096 Len=27740 [TCP segment of a reassembled PDU]

According to the ACK packet, there is enough room in the recv window, but somehow the packet is ignored. After 5 unsuccessful retransmission, the sender eventually drops the connection.

Thanks.

edit retag flag offensive close merge delete

Comments

Without a trace it is hard to say, camn you share us a trace: https://blog.packet-foo.com/2016/11/t.... And the receiver side is done with Segmentation Offloading which does not reflect the situation on the wire.

Christian_R gravatar imageChristian_R ( 2018-07-18 11:01:20 +0000 )edit

Hello, Christian. Thanks, I uploaded the receiver capture on Google Drive: https://drive.google.com/open?id=1V1m...

The capture shows the connection established at 15:35:47 from port 64613 to 14004. The TCP conversation goes on for almost a minute, transferring amount of data, with occasions of congestion in both directions.

The issue seems to start at 15:36:20.526157000: from this time on, the receiver seems to ACK seq=3020828 for each of the 5 packet retransmissions, until the connection RESET, received at 15:36:39.431508000 (when the Windows sender gives up and closes the connection).

Luca gravatar imageLuca ( 2018-07-18 12:25:26 +0000 )edit

The capture file appears to have been taken on the machine with IP 192.168.50.157. Is there a corresponding capture file available from the other side, namely at 192.168.195.45?

cmaynard gravatar imagecmaynard ( 2018-07-18 18:43:12 +0000 )edit

Yes, cmaynard. Note the registrations were sanitized via TraceWrangler, so the IPs will appear randomized. I do have the corresponding registration from the connection peer: I will just upload and make it available tomorrow, when I can access the registration file again. Thanks!

Luca gravatar imageLuca ( 2018-07-18 19:07:44 +0000 )edit

The problem is very strange. The missed 1460 byte segment w/seq # 3020828 is retransmitted with the next seq # correctly indicating 3022288; yet 192.168.195.45 continues to only ack 3020828. It would appear that 192.168.195.45 never receives it, but the capture file from the other side would confirm or deny that.

cmaynard gravatar imagecmaynard ( 2018-07-18 19:17:31 +0000 )edit

1 Answer

Sort by » oldest newest most voted
2

answered 2018-07-19 15:49:31 +0000

cmaynard gravatar image

Given the 2 supplied capture files ...

I used Tracewrangler to restore the original IP's, namely 192.168.195.45 => 10.247.166.16 and 192.168.50.157 => 172.28.12.164 to more easily compare them and to be able to refer to the same IP addresses in both capture files.

The captures were apparently taken with a snaplen of 54 bytes, which is a bit unfortunate as we don't have full frames for checksum verification. That said, I focused on a single packet, namely the 1st retransmission of the 1460 byte segment being sent from 10.247.166.16 to 172.28.12.164 with sequence # 3020828.

In the snd.pcapng file, this is frame #58376; in the recv.pcapng file, this is frame #13878. Comparing these 2 frames, the only differences are:

  • TTL: It is 128 in snd.pcapng and 127 in recv.pcapng. This TTL difference was already noted by Packet_vlad.
  • TCP Checksum: It is 0x3f4f (unverified) in snd.pcapng and 0x31fa (unverified) in recv.pcapng.

Unfortunately, the TCP checksums can't be verified because of the snaplen used. That said, the TCP Checksums should be identical since TTL isn't included as part of the 96-bit pseudo header that goes into the TCP Checksum algorithm. The TCP checksums would/could differ though if:

  • There was some NAT'ing going on, in which case the IP addresses could have changed. Is this the case?
  • TCP Checksum Offloading is being done on the sender side, in which case 0x3f4f might not be the actual TCP checksum that was calculated and transmitted. If this could be the case, then it would be better to capture outside of the 10.247.166.16 host.

It might be worthwhile to capture both sides again, but without applying a snaplen.

In any case, IF the TCP checksum is wrong when the TCP segment arrives at its destination, then this would explain why the receiver never ACK's it.

edit flag offensive delete link more

Comments

The checksum can be wrong, but it also can be due to offloading at least in the trace with the huge frames.

Christian_R gravatar imageChristian_R ( 2018-07-19 18:01:58 +0000 )edit

I thought about that but how to explain such selectiveness - only original segment with sequence # 3020828 and all its subsequent retransmissions were dropped, while all of them had different checksums (because of different TCP ACK fields). At the same time none of pure ACKs from the same source was dropped.

Packet_vlad gravatar imagePacket_vlad ( 2018-07-19 19:26:53 +0000 )edit

I guess, that the packets get stuck in the queue of the stack, as we can see that the stack is under stress due the advertised RWin of 4096. So I agree with Vladimir slowing down the traffic could be tried.

Christian_R gravatar imageChristian_R ( 2018-07-19 20:43:40 +0000 )edit

Thanks, Maynard. This is a good hint - unfortunately, the original registrations are complete (possible that TraceWrangler truncates the payloads).

From Wireshark, I enabled checksum verification on the receiver, and the checksum are indeed correct, according to Wireshark.

Additional note: yes, there is Checksum Offloading enabled on both side, so checksum can only be verified on the registration side showing packet receive.

Luca gravatar imageLuca ( 2018-07-20 08:15:08 +0000 )edit

Thanks, @Christian_R and @Packet_vlad. I see all the points about reducing/slowing down the traffic by tuning the TCP window scaling factor and the TCP buffer size. And they are indeed very pertinent. But both seems palliative actions: I would like to understand which is the root cause of the TCP behavior here and why the back pressure is not activated on the sender side.

Luca gravatar imageLuca ( 2018-07-20 08:33:17 +0000 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower

Stats

Asked: 2018-07-18 08:13:13 +0000

Seen: 6,304 times

Last updated: Jul 19 '18