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How to save in a variable a specific value from masked bytes?

asked 2021-08-18 07:18:35 +0000

lluc_fn gravatar image

updated 2021-08-18 07:22:25 +0000

The variable YEAR, has got an offset of 2000. This means, that I need to add 2000 to the taken value. Here I create my "ProtoField":

local Year_proto = ProtoField.uint16("Variable_Year", "This is the transmitted year", base.DEC, nil)

Before adding it to the shown values of my Wireshark-Parser, I need to save the LITTLE-ENDIAN 7 bits long number. The bit mask should be 0x07f0 = 0000 0111 1111 0000 - so the only intersting bits here are the "1". The start byte is the 77 and the information is found in two bytes (buffer(77,2).

Can you please tell me how can I save the mentioned LITTLE-ENDIAN 7 bits number? Let's say that the name of the saved number is saved in "year_test" and the variable "year" is the corrected value:

year=year_test+offset //for example year_test=0x15=21 --> 2021

Afterwards I would list the corrected year value as follows:

subtree:add(Year_proto, year)

Many thanks for your help!

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What do you mean by LITTLE-ENDIAN 7 bits number? You mentioned that, "The bit mask should be 0x07f0 = 0000 0111 1111 0000", so assuming bits are numbered from left-to-right as bits 15-0, does that mean that only bits 11-4 are relevant but that bit 11 is the least-significant bit and bit 4 is the most significant bit?

cmaynard gravatar imagecmaynard ( 2021-08-23 14:39:52 +0000 )edit

Let's say that the two bytes are 0x50 and 0x41. 0x50 is byte #77 and 0x41 is byte #78. As is LITTLE-ENDIAN, the bites more to the left from #78 are the MSB. So that: 0x4150=0100 0001 0101 000, with the mask 0x7F0 I just care the following 7 bits: 001 0101 = 0x15 = 21 (to that 21 decimal I need to add 2000). I hope it answers your question, many thanks again for your help! :)

lluc_fn gravatar imagelluc_fn ( 2021-08-24 08:14:49 +0000 )edit

OK, so the bitfield is split across a multi-byte field, which is transmitted in Little-Endian format but the 7 bits that comprise the field itself are specified in the "normal" order with the most-significant bit on the left and the least-significant bit on the right.

cmaynard gravatar imagecmaynard ( 2021-08-24 15:37:29 +0000 )edit

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answered 2021-08-24 15:51:25 +0000

cmaynard gravatar image

Ideally you could accomplish this as follows:

local Year_proto = ProtoField.uint16("Variable_Year", "This is the transmitted year", base.DEC, nil, 0x07f0)

subtree:add_le(Year_proto, buffer(77, 2), 2000 +, 2):le_uint(), 4), 0x7f))

That would highlight the 7 bits of the multi-byte field while still being able to specify the exact value to display, but unfortunately Wireshark is applying the 0x07f0 mask to the specified value, which I believe is a bug, after all the user is explicitly indicating the value to be displayed. In any case, because of this problem, you have to declare Year_proto as follows:

local Year_proto = ProtoField.uint16("Variable_Year", "This is the transmitted year", base.DEC)

The down-side here is that the relevant bits of the multi-byte field will not be shown in the tree as they otherwise would be.

For more information on the Lua BitOp Module, refer to This is necessary because we're still stuck on Lua 5.2, which doesn't support native bitops, which are supported by Lua 5.3.

See also some related Lua 5.2 -> 5.3 discussions on the wireshark-dev mailing list:

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Many thanks for your help, it works! Even if that the exactly selected bits are not shown, the solution solved my problem.

lluc_fn gravatar imagelluc_fn ( 2021-08-25 08:02:49 +0000 )edit

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Asked: 2021-08-18 07:18:35 +0000

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Last updated: Aug 24