Ask Wireshark - RSS feedhttps://ask.wireshark.org/questions/Wireshark questions and answersenCopyright Wireshark Foundation, 2017-2020Sun, 23 Sep 2018 14:41:52 +0000I am attempting to calculate the Mbps of an IO graph. The y axis appears to jump to 1*10^6 after 999,999 bytes. Why is the exponent a 6?https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/I am attempting to calculate the Mbps of an IO graph. The y axis appears to jump to 1\*10^6 after 999,999 bytes. Why is the exponent a 6? After another million bytes the exponent goes to a 7. I feel that I am calculating something wrong. According to my graph the peak Bytes per second is around 6\*10^7 from the 4 second mark to the 6 second mark. I am calculating this to be 60,000,000 Bytes. I then divide that by 125,000 to get 480 Mbps. Is this correct? I feel the exponents are throwing me off and questioning if I am interrupting the y axis correctly.
ThanksSun, 23 Sep 2018 06:54:16 +0000https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/Answer by Packet_vlad for <p>I am attempting to calculate the Mbps of an IO graph. The y axis appears to jump to 1*10^6 after 999,999 bytes. Why is the exponent a 6? After another million bytes the exponent goes to a 7. I feel that I am calculating something wrong. According to my graph the peak Bytes per second is around 6*10^7 from the 4 second mark to the 6 second mark. I am calculating this to be 60,000,000 Bytes. I then divide that by 125,000 to get 480 Mbps. Is this correct? I feel the exponents are throwing me off and questioning if I am interrupting the y axis correctly.</p>
<p>Thanks</p>
https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/?answer=5154#post-id-5154This is just [scientific notation](https://en.wikipedia.org/wiki/Scientific_notation) of the numbers you say.
1x10^6 is not a *jump* from 999,999, it's just 1,000,000 or one million represented in such way because this is more compact.
So, 6x10^7 is exactly 60 million (six followed by 7 zeros). A benefit of this increases with large numbers (which one is easier to interpret for 100 million - 1x10^8 or 100000000?).
There is no error in your calculations and in IO graph too. The only thing that confuses you is notation type.
Keep in mind also if you change "interval" value - Y axis will also be changed.Sun, 23 Sep 2018 07:35:55 +0000https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/?answer=5154#post-id-5154Comment by Tolein for <p>This is just <a href="https://en.wikipedia.org/wiki/Scientific_notation">scientific notation</a> of the numbers you say.
1x10^6 is not a <em>jump</em> from 999,999, it's just 1,000,000 or one million represented in such way because this is more compact.</p>
<p>So, 6x10^7 is exactly 60 million (six followed by 7 zeros). A benefit of this increases with large numbers (which one is easier to interpret for 100 million - 1x10^8 or 100000000?).</p>
<p>There is no error in your calculations and in IO graph too. The only thing that confuses you is notation type. </p>
<p>Keep in mind also if you change "interval" value - Y axis will also be changed.</p>
https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/?comment=5159#post-id-5159Oh I see now. It was right in front of me. Thanks so much for the explanation.Sun, 23 Sep 2018 14:41:52 +0000https://ask.wireshark.org/question/5153/i-am-attempting-to-calculate-the-mbps-of-an-io-graph-the-y-axis-appears-to-jump-to-1106-after-999999-bytes-why-is-the-exponent-a-6/?comment=5159#post-id-5159